Apply Function To Masked Numpy Array
Solution 1:
For that specific function, few approaches could be listed.
Approach #1 : You can use boolean indexing
for in-place setting -
img[mask] = (img[mask]*0.5).astype(int)
Approach #2 : You can also use np.where
for a possibly more intuitive solution -
img_out = np.where(mask,(img*0.5).astype(int),img)
With that np.where
that has a syntax of np.where(mask,A,B)
, we are choosing between two equal shaped arrays A
and B
to produce a new array of the same shape as A
and B
. The selection is made based upon the elements in mask
, which is again of the same shape as A
and B
. Thus for every True
element in mask
, we select A
, otherwise B
. Translating this to our case, A
would be (img*0.5).astype(int)
and B
is img
.
Approach #3 : There's a built-in np.putmask
that seems to be the closest for this exact task and could be used to do in-place setting, like so -
np.putmask(img, mask, (img*0.5).astype('uint8'))
Post a Comment for "Apply Function To Masked Numpy Array"