How To Get 1000 Records From Dataframe And Write Into A File Using Pyspark?

I am having 100,000+ of records in dataframe. I want to create a file dynamically and push 1000 records per file. Can anyone help me to solve this, thanks in advance.

Solution 1:

You can use maxRecordsPerFile option while writing dataframe.

• If you need whole dataframe to write 1000 records in each file then use repartition(1)(or) write 1000 records for each partition use .coalesce(1)

Example:

# 1000 records written per file in each partition
df.coalesce(1).write.option("maxRecordsPerFile", 1000).mode("overwrite").parquet(<path>)

# 1000 records written per file for dataframe 100 files created for100,000
df.repartition(1).write.option("maxRecordsPerFile", 1000).mode("overwrite").parquet(<path>)

#or by set config on spark session
spark.conf.set("spark.sql.files.maxRecordsPerFile", 1000)
#or
spark.sql("set spark.sql.files.maxRecordsPerFile=1000").show()

df.coalesce(1).write.mode("overwrite").parquet(<path>)
df.repartition(1).write.mode("overwrite").parquet(<path>)

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Method-2:

Caluculating number of partitions then repartition the dataframe:

df = spark.range(10000)

#caluculate partitions
no_partitions=df.count()/1000from pyspark.sql.functions import *

#repartition and check number of records on each partition
df.repartition(no_partitions).\
withColumn("partition_id",spark_partition_id()).\
groupBy(col("partition_id")).\
agg(count("*")).\
show()

#+-----------+--------+#|partiton_id|count(1)|#+-----------+--------+#|          1|    1001|#|          6|    1000|#|          3|     999|#|          5|    1000|#|          9|    1000|#|          4|     999|#|          8|    1000|#|          7|    1000|#|          2|    1001|#|          0|    1000|#+-----------+--------+

df.repartition(no_partitions).write.mode("overwrite").parquet(<path>)

Solution 2:

Firstly, create a row number column

df = df.withColumn('row_num', F.row_number().over(Window.orderBy('any_column'))

Now, run a loop and keep saving the records.

for i in range(0, df.count(), 1000):
   records = df.where(F.col("row_num").between(i, i+999))
   records.toPandas().to_csv("file-{}.csv".format(i))