Removing Six.b From Multiple Files

I have dozens of files in the project and I want to change all occurences of six.b('...') to b'...'. Can I do that with some sort of regex bash script?

Solution 1:

It's possible entirely in Python, But I would first make a backup of my project tree, and then:

import re
import os

indir = 'files'for root, dirs, files in os.walk(indir):
    for f in files:
        fname = os.path.join(root, f)
        withopen(fname) as f:
            txt = f.read()
        txt = re.sub(r'six\.(b\("[^"]*"\))', r'\1', txt)
        withopen(fname, 'w') as f:
            f.write(txt)
        print(fname)

Solution 2:

A relatively simple bash solution (change *.foo to *.py or whatever filename pattern suits your situation):

#!/bin/bashexport FILES=`find . -type f -name '*.foo' -exec egrep -l 'six\.b\("[^\"]*"\)' {} \; 2>/dev/null`
for file in$FILESdocp$file$file.bak
    sed 's/six\.b(\(\"[^\"]*[^\\]\"\))/b\1/'$file.bak > $fileecho$filedone

Notes:

1. It will only consider/modify files that match the pattern

2. It will make a '.bak' copy of each file it modifies

3. It won't handle embedded \"), e.g. six.b("asdf\")"), but I don't know that there is a trivial solution to that problem, without knowing more about the files you're manipulating. Is the end of six.b("") guaranteed to be the last ") on the line? etc.