Print A Diamond Of Numbers In Python

1 121 12321 1234321 123454321 1234321 12321 121 1 I can only print stars but have no logic for numbers. userInput = int(input('Please input s

Solution 1:

The following can do this concisely using a helper function:

defup_and_down(n):  # 1,2, ..., n, ..., 2, 1return (*range(1, n), *range(n, 0, -1))

defdiamond(n):
    for i in up_and_down(n):
        print((n-i)*' ', *up_and_down(i), sep='') 
       
>>> diamond(5)
    11211232112343211234543211234321123211211

Solution 2:

for i in range (1,6):

for j in range(6-i):
    print(" ", end=" ")

for k in range(1,i):
    print(k, end = " ")

for l in range(i, 0, -1):
    print(l, end= " ")


print() 

for i in range (4,0,-1): for j in range(6-i): print(" ", end=" ")

for k in range(1,i):
    print(k, end = " ")

for l in range(i, 0, -1):
    print(l, end= " ")
print()

Solution 3:

Another (very simple) way to handle this is to take advantage of:

1. The call stack.
2. The mathematical property of elevens where: n = a^2.

For example:

• 1 = 1^2
• 121 = 11^2
• 12321 = 111^2
• 1234321 = 1111^2
• etc ...

Example Function:

defdiamond(n, c=1):
    """Print a diamond pattern of (n) lines.

    Args:
        n (int): Number of lines to print.

    """
    string = f'{int("1"*c)**2:^{n}}'if c < (n//2)+1:
        print(string)
        diamond(n=n, c=c+1)
    if c <= n:
        print(string)

>>> diamond(7)

Output:

   1   
  121  
 12321 
1234321
 12321 
  121  
   1   

Implementation Note:

There are different ideas as to whether n applies to the number of lines printed, or the center value of the diamond. This example implements the former; but is easily modified to implement the latter.